Using the Wizard's formula, the variance for betting one unit on each of six hands would be: 6(1.303)+6(5)(0.479) = 22.188. And the Wizard gives 0.479 as the covariance for those rules. In your example, the standard deviation is 1.14149, which makes the variance 1.14149 2 = 1.303, which is the variance for a hand of 6-deck, DAS, surrender, re-split aces blackjack.

He gives this formula for the total variance for playing n hands each of bet 1 unit: nv + n(n-1)c, where v is the variance for each hand and c is the covariance between each hand. Here's the Wizard's page on Variance in Blackjack: The following reply applies to playing six hands of blackjack in one round. If the standard deviation in Blackjack is 1.14149, how does that differ if you play multiple hands?Īs an example, what is the difference in playing one Blackjack hand at $60,000 versus playing six Blackjack hands at $10,000? How much more risky is it to play the one hand at $60,000 versus spreading the same $60,000 over six hands?

I am wondering how to calculate the standard deviation on a Blackjack game for one hand versus multiple hands.

Deviation blackjack 18